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32-3x^2=10x
We move all terms to the left:
32-3x^2-(10x)=0
a = -3; b = -10; c = +32;
Δ = b2-4ac
Δ = -102-4·(-3)·32
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-22}{2*-3}=\frac{-12}{-6} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+22}{2*-3}=\frac{32}{-6} =-5+1/3 $
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